I has __ pens less than the ___.
1. LABOUR has one pen less than K.J has four pens more than the MD. K doesn’t have 8 pens. So, LABOUR has either 2 or 3 pens. J has either 7 or 6 pens 2. H is the SE, this is not possible in case I, so case I is rejected. 3. L has fewer pens than M but not the lowest. So, H has 7 pens. L has 3 pens, M has 8 pens. I has 2 pens and is the MD. 4. DR has more pens than the PM but not the highest. So, J is the DR, K is the PM and thus, M is the TL. The final table is given below:
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