If Sanjay and the person who have Red interchange their visiting days then how many persons visits after the person who likes BLACK colour?
We have: The one, who visits Rampur, visits on any day after Friday, that means we have two possible day for the one who visits Rampur, in case (1) the one who visits Rampur, visits on Saturday, in case (2) the one who visits Rampur, visits on Sunday. There were two days gap between the one, who likes Yellow and Happy who visits Rampur. Raman visits Lucknow on Tuesday. There were two days gap between Raman and the one who likes Green. The one, who visits Kanpur, visits on adjacent day of the one who likes Green, that means we have three possible day for the one who visits Kanpur, in case (1) & case (2a) the one who visits Kanpur visits on Thursday, in case (2b) the one who visits Kanpur visits on Saturday. Based on above given information we have: Again, we have: Aadil neither visits on adjacent day of the one likes Yellow nor on adjacent day of Happy. One person visits between the one who visits Jhansi and Aadil, who has Red, that means Aadil visits on Monday. There were three days gap between the one who likes Pink and the one who visits Jhansi. Sanjay neither likes Pink nor he visits before the one who visits Kanpur and he visits Saharanpur. There were two days gap between Sanjay and the one who likes White, who visits on adjacent day of the one who likes Yellow, that means case (2b) is not valid, in case (1) Sanjay visits on Friday, in case (2a) Sanjay visits on Saturday. Based on above given information we have:
Case (2b) is not valid as Sanjay doesn’t visit before the one who visits Kanpur. Again, we have: The one who likes Black and Farun visits on adjacent days. There were three days gap between Farun and the one who visits Meerut, that means in case (1) Farun visits on Wednesday, in case (2) Farun visits on Friday. Neither Farun nor Yogesh visits Meerut, that means in case (1) Yogesh visits Kanpur. At least three person visits between the one, who visits Bareilly and the one, who has Blue, that means case (2a) is not valid. Based on above given information we have final arrangement we have:
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