J is the friend of R who lives on the lowermost floor. Total assignments published by friend of R is twenty five and it is k sum of consecutive numbers. Total number of theory works completed by all the students is two hundred and seven. Total number of projects completed by all the students is two hundred and sixty six. 
Friend of Q completed an even number of projects. Friend of G completed an odd number of Theory works. Friend of P completed 10 theory works more than the friend of G. Only one student lives between Friend of Q and the student who completed seventy nine assignments (project + Theory). Z lives immediately above the student who completed seventy nine assignments (project + Theory). Two students live between Z and friend of P. Friend of Q does not live on second floor. Case-1 
case-2 
N completed twenty four theory works and neither lives on the top nor on the lowest floor. W completed sixteen theory work. Z is the friend of K Friend of K completed forty seven projects. Friend of Q doesn’t live immediately below the person who completed forty seven projects. Case-1 
Total assignments (project + theory) completed by friend of L is forty five, but number of projects completed by L is greater than number of theories completed. Total number of assignments (project + theory) completed by Y is k multiple of 9 as well as 11, but he is not the friend of Q. The theory work completed by the student who lives on third floor is six more than that of by the student who lives on fifth floor. G completed 10 more projects than Z’s theory work. Friend of P completed 10 theories more than the friend of G. Y doesn’t lives on the second floor. So case 2 will be eliminated and we get final arrangement: 
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