Note: They secure different marks in Science viz., 5, 16, 19, 20, 24, 36 and 57.The persons who is studying in 8th class secure only even number marks and the person who study 10th class secure only Odd number marks. The sum of marks secure by H and W is more than 90 marks.(H/W=57/36) Q and D only studying in class 7. ( Q and D secure = 5/19 marks) Q secure more marks than D. So Q secure 19 marks and D secure 5 marks. A Secured less than 30 marks and studies with W. A secure more marks than G. So A secure either 20 or 24. A and E studying in different class. G and W studying in the same class. A and H studying in different class. A is junior to H. From this E and H studying in class 5. A, G and W are studying in class 6. The mark scored by E is not a multiple of 5. E and G secure a mark which is a multiple of 4. So the final arrangement becomes
Find the remainder when 413 is divided by 5.
A six-digit number 23p7q6 is divisible by 24. Then the greatest possible value for (p + q) is:
which of the following pairs of non-zeroes values of p and q make the 6-digit number 674pq0 divisible by both 3 and 11?
18 is divided into three parts which are in arithmetic progression (A.P.) in such a way that the sum of their square is 158. Find the square of the sum
The greatest number that will divide 398,436, and 542 leaving 7, 11, and 15 as remainders, respectively, is:
If the 6-digit number 1344AB is divisible by 3, 7, and 11, then what is the value of A + B?
476xy0 is divisible by both 3 and 11. The non-zero digits in the hundreds and tens places are respective.
The greatest number that will divide 398, 437 and 5425 leaving 7, 12 and 2 as remainders, respectively, is:
Which of the following pairs of non-zero values of p and q make 6-digit number 674pq0 divisible by both 3 and 11?
21 is divided into three parts which are in arithmetic progression (A.P.) in such a way that the sum of their square is 155. Find the smallest part.