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1. G lives three floors above K. G and K lives in same flat. 2. L lives somewhere to the south west of G. 3. H lives immediately below L but not to the south west of K.H and L lives in same flat. So, G lives in flat B. G lives on either floor 4 or floor 5. Case I: G lives on floor 4: 4. J lives two floors above M. 5. E lives south east of M, this is not possible in case I(a) and case II, so case I(a), case II(a) and case II(b) are rejected. So, J lives on floor 5 of flat A. M lives on floor 3 of flat A. E lives on floor 2 of flat B
7. F lives to the north east of D.M and J lives in same flat. So, D lives on floor 4 of flat A. F lives on floor 5 of flat B. I lives on floor 3 of flat B. The final table is given below:
Three of the following four letter-clusters are alike in a certain way and one is different.
Pick the odd one out.
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Four letter-clusters have been given out of which three are alike in some manner and one is different. Select the odd one.
Select the option figure in which the given figure is embedded (rotation is NOT allowed).
If ‘DONKEY’ is coded as ’88’ and ‘SPARROW’ is coded as ’79, then how will ‘PEGION’ be coded?
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Select the letter triad from the given options which follows the same relation as shown below.
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