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We have, D completed the training three years after F. Only three persons completed the training between C and F. C doesn’t complete on an odd numbered year. From the above condition, there are three possibilities Again we have, The number of persons completed before D is one more than the number of persons completed after B. Only one person completed the training between B and A.
Again we have, The difference between the years in which G and E completed is three years. Both H and E completed the training in consecutive years. So Case2 and 3 get eliminated, hence the final arrangement becomes
24% of 400 × 16% of ? = 384
[{70 + (40 - 22) ÷ 3} ÷ 4] = ?
22 * 6 + 45% of 90 + 65% of 180 = ?
[(36 × 15 ÷ 96 + 19 ÷ 8) × 38] = ?% of 608
36×?² + (25% of 208 +13) = 60% of 2400 + 17×18
(360 - ?)/(25% of 96) = 13
Solve.
15.73 +13.25 +16.73 – 28.71 = 5 ×?
(11/12) × (18/22) × (4/3) + 3 = ?2