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We have, D completed the training three years after F. Only three persons completed the training between C and F. C doesn’t complete on an odd numbered year. From the above condition, there are three possibilities 
Again we have, The number of persons completed before D is one more than the number of persons completed after B. Only one person completed the training between B and A. 
Again we have, The difference between the years in which G and E completed is three years. Both H and E completed the training in consecutive years. So Case2 and 3 get eliminated, hence the final arrangement becomes 
Statements:
B > C = Z ≥ Q ≥ O; X < C ≤ D < O
Conclusions:
I. O > X
II. B > O
Statements: M ≥ O ≥ P ≤ W, N ≥ K ≥ Y = M
Conclusion:
I. N > W
II. Y ≥ P
Statements: W ≤ B = F; H > T; H < U < F; W ≤ X < S
Conclusions:
I. W < U
II. T < B
III. X > H
Statements: X < Y < Z = L, R = S > T, T ≥ U < V = W > X
Conclusions:
I. R > Y
II. W < L
III. S > X
Statements: P # Q @ R & S @ T # W % I, K $ S @ L
Conclusions: I. Q # W II. R & L
...Statement: Y < Z > I < Q > S = M ≤ N
Conclusions:
I. S= N
II. Q > M
Statements: R ≤ K ≤ H = O ≥ D > Q; K > P
Conclusions:I. O ≥ Q II. Q > P
Statements: Q > U = V ≤ X; R ≥ S ≥ X
Conclusions:
I. U = S
II. V < S
Statements: I % C, C & D, D $ K, K # Z
Conclusions: I. I & D II. D # Z
...Statements: B ≥ C > D; B < E > J; G > A ≥ H > J
Conclusion:
I. D ≤ A
II. G > C
