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    Question

    Answer the questions based on the information given below. There are six items P, Q, R, S, T and U. Each of the items has different weight. P is heavier than S but lighter than U. The weight of second heaviest item is 58kg. The weight of the second lightest item is 35kg. The weight of Q is more than the weight of S and T, which is the lightest among all. U is not the heaviest item. R is lighter than P.

    If the difference between the weights of U and R is

    23kg, then how many items are lighter than the item S?
    A Two Correct Answer Incorrect Answer
    B Three Correct Answer Incorrect Answer
    C One Correct Answer Incorrect Answer
    D None Correct Answer Incorrect Answer
    E Four Correct Answer Incorrect Answer

    Solution

    P is heavier than S but lighter than U. The weight of Q is more than the weight of S and T, which is the lightest among all. U is not the heaviest item. R is lighter than P. U > P > S Or Q > S > T Also, T is the lightest among all and U is not the heaviest. So, Q must be the heaviest item among all. The final arrangement is as follows: Q > U(58) > P > S/R > R/S (35) > T If the difference between the weights of U and R is 23kg, then weight of R must be 35kg which means item S is heavier than R.

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