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Start learning 50% faster. Sign in nowSTEP I: P sits third to the left of M who sits an immediate neighbour of O. Three persons sit between J and O who sits second to the left of K. As per these statements, we can say that there are three possible cases and the arrangement will look like this:
STEP II: L sits to the immediate left of N who sits second to the left of P. Both L and J sit adjacent to each other. The number of persons sits between N and O is one less than the number of persons sits between O and L when counted from the right of both N and O respectively. At least one person sits between K and L when counted from the right of K. As per these statements, CASE I and CASE III get eliminated and we continue with CASE II and the final arrangement will look like this:
1000÷ 250 = ( 3√? × √1444) ÷ ( 3√512 × √361)
Solve.
15.73 +13.25 +16.73 – 28.71 = 5 ×?
If √3n 729, then the value of n is equal to:
?% of 120 × 3√343 = 42 × 20
(64/25)? × (125/512)?-1 = 5/8
(-251 × 21 × -12) ÷ ? = 158.13