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STEP I: P sits third to the left of M who sits an immediate neighbour of O. Three persons sit between J and O who sits second to the left of K. As per these statements, we can say that there are three possible cases and the arrangement will look like this:
STEP II: L sits to the immediate left of N who sits second to the left of P. Both L and J sit adjacent to each other. The number of persons sits between N and O is one less than the number of persons sits between O and L when counted from the right of both N and O respectively. At least one person sits between K and L when counted from the right of K. As per these statements, CASE I and CASE III get eliminated and we continue with CASE II and the final arrangement will look like this:
Statement: A ≥ B > I > E ≤ P, E = S ≥ P
Conclusion: I. A ≥ P II. B > P
How is Q related to O?
If N has only one child and there are four male members in the family then how is the child of N related to L?
D is the brother of C. E is the sister of F, who is the son of B. G is the daughter-in-law of C. F is married to G. C is not a male. How is D related to B?
How is H related to L?
If F$E@I*G&H&J then how is H related to E?
How is H related to C?
How is Q related to O?
How is S related to T?