Get Started with ixamBee
Start learning 50% faster. Sign in now
X attends singing class only after one person and has tuition neither in Ranchi nor in Noida. P attends singing class on Tuesday and has tuition in Meerut. Only three person attend singing class between P and T who do not have her tuition in Kanpur. Only three person attend singing class between Y and W but W attends singing class after P. Neither Y nor W attends singing class on Wednesday. So, there can be two possibilities- 
Y does not attend singing class in evening. From this case-2 will get eliminated. The one who attends class on Thursday has tuition centre in Kanpur. Both S and Q attend singing class on same day. Four person attend singing class between V and S. V attends singing class before S and has tuition centre in Lucknow. Both who has tuition centre in Pune and Dehradun attends singing class on same day. Q does not has tuition centre in Dehradun. U attends singing class immediately before R who has tuition centre in Delhi. 
Statements:
B > C = Z ≥ Q ≥ O; X < C ≤ D < O
Conclusions:
I. O > X
II. B > O
Statements: M ≥ O ≥ P ≤ W, N ≥ K ≥ Y = M
Conclusion:
I. N > W
II. Y ≥ P
Statements: W ≤ B = F; H > T; H < U < F; W ≤ X < S
Conclusions:
I. W < U
II. T < B
III. X > H
Statements: X < Y < Z = L, R = S > T, T ≥ U < V = W > X
Conclusions:
I. R > Y
II. W < L
III. S > X
Statements: P # Q @ R & S @ T # W % I, K $ S @ L
Conclusions: I. Q # W II. R & L
...Statement: Y < Z > I < Q > S = M ≤ N
Conclusions:
I. S= N
II. Q > M
Statements: R ≤ K ≤ H = O ≥ D > Q; K > P
Conclusions:I. O ≥ Q II. Q > P
Statements: Q > U = V ≤ X; R ≥ S ≥ X
Conclusions:
I. U = S
II. V < S
Statements: I % C, C & D, D $ K, K # Z
Conclusions: I. I & D II. D # Z
...Statements: B ≥ C > D; B < E > J; G > A ≥ H > J
Conclusion:
I. D ≤ A
II. G > C
