Question
Four out of five pair follow a certain rule and thus
form a group, then which of the following pair doesn’t belong to that group? Study the following information carefully and answer the below questions. Eight friends namely – J, W, X, Z, Y, A, E and F sits in a row in such a way that some are facing north while some are facing south. Each person sits at a gap of either 1m, 2m or 3m. Distance between at least two and not more than three person are same. None of the adjacent persons sit at same distance. Each person also likes different numbers from 1 to 8. No two adjacent persons like consecutive numbers. All the information is not necessarily in the same order. Z sits third to right of the one who likes 3. Z neither sits adjacent to A nor likes even number. F neither sits at end of the row nor sits adjacent to W. The one who likes 2 sits 5m from left end. Two persons sit between the one who likes 2 and F, who likes 8. Z sits 6m right of Y. A sits immediate right of the one who likes 6. W sits 4m left of the one who likes 8 and is 1m right of the one who likes 5. X sits 7m left of the one who likes 7. Y sits immediate right of the one who likes 1. The one who likes 5 sits three places away from A, who doesn’t like odd number. F sits facing north. The one who likes 4 sits 2m away from X. J sits 8m left of E, who neither likes prime number nor sits adjacent to the one who likes 4. Y and A sits facing in same direction but opposite to the direction of J.Solution
We have: The one who likes 2 sits 5m from left end, since only such combinations are (2, 3), (1, 1, 3) & (1, 2, 2). Two person sits between the one who likes 2 and F, who likes 8 and sits facing north. F neither sits at end of the row nor sits adjacent to W, that means we have four possible cases, in case (1) the one who likes 2 sits (2 + 3)a from left end, in case (2) the one who likes 2 sits (3 + 2)a from left end, in case (3) the one who likes 2 sits (1 + 3 + 1)a sits from left end, in case (4) the one who likes 2 sits (2 + 1 + 2)a from left end. W sits 4m left of the one who likes 8 and is 1m right of the one who likes 5, since only possible such combination is (1, 4). The one who likes 5 sits three places away from A, who doesn’t like odd number. A sits immediate right of the one who likes 6, thus in case (1a) A sits at right end and the one who likes 5 sits fourth from right end, in case (1b) A sits second from left end and the one who likes 5 sits fourth from right end, in case (2a) A sits at right end and the one who likes 5 sits fourth from right end, in case (2b) A sits second from left end and the one who likes 5 sits fourth from the right end, in case (3) & case (4) A sits third from left end and the one who likes 5 sits third from right end. Based on above given information we have
Again, we have: Z sits third to right of the one who likes 3, since none of the adjacent person likes consecutive numbers. Z neither sits adjacent to A nor likes even number, that means in case (1a), case (1b), case (2a) & case (2b) the one who likes 3 sits at right end facing south and case (3) & case (4) are not valid. The one who likes 4 sits 2m away from X. X sits 7m left of the one who likes 7, thus in case (1a) & case (1b) X sits at left end and W likes 7, in case (2b) X sits at right end and W sits facing south. Based on above given information we have: Case-1a
Case (3) & case (4) are not valid as Z sits third to right of the one who likes 3 and case (2a) is not valid as X sits 7m left of the one who likes 7. Again, we have: Y sits immediate right of the one who likes 1. J sits 8m left of E, who neither likes prime number nor sits adjacent to the one who likes 4, that means in case (1a) & case (1b) J sits third from left end and E sits facing north, case (2b) is not valid. Z sits 6m right of Y, that means distance between E and Y is 1m and case (1a) is not valid. Y and A sits facing in same direction but opposite to the direction of J, that means A sits facing south and J sits facing North. Based on above given information we have final arrangement as follow: Case (2b) is not valid as J sits 8m left of E and case (1a) is not valid as Z sits 7m right of Y. Case-1b
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