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We have: J sits at either end of the row three places away from the one who likes Strawberry. The one who likes Strawberry sits facing S. One person sits between S and the one who likes Guava, that means in case (1) J sits at left end of row 1, in case (2) J sits at right end of row 2. Two person sits between V and the one who sits facing G. G neither likes Strawberry nor sits facing U. G sits immediate right of the one who likes Watermelon, that means in case (1) V sits at left end of row 2, in case (2) V sits at right end of row 2. Based on above given information we have: Case-1 Again, we have: The one who likes Orange and the one who likes Papaya sits together. The one who likes Papaya, sits facing the one, who sits second to left of the one who likes Banana. The one who likes Banana neither sits at end of the row nor sits in same row of the one who likes Apple. The one who likes Orange sits facing the one who likes Mango, that means in case (2a) the one who likes Papaya sits second from right end of row 2, in case (2b) the one who likes Papaya sits second from right end of row 1, case (1) is not valid. I sits facing the one who likes Pineapple and is adjacent to F. F neither sits facing the one who likes Banana nor sits facing T, that means in case (2a) I likes Watermelon and case (2b) is not valid. Based on above given information we have: Case-2a
Case (1) is not valid as the one who likes Papaya, sits facing the one, who sits second to left of the one who likes Banana & case (2b) is not valid as F neither sits facing the one who likes Banana nor sits facing T. Again, we have: Since, the one who likes Banana and the one who likes Apple doesn’t sit in same row, that means the one who likes Apple sits at left end of row 2. One person sits between U and T. T neither sits facing the one who likes Grapes nor sits facing the one who likes Orange, that means U sits at left of the row 2. As, the only remaining person is R, thus R likes Guava. Based on above given information we have final arrangement as follow:
Match List I with List II :
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