S stands second to the left of M. The girl who likes J stands on the immediate left of M. P likes neither F nor I and faces S, who likes neither J nor L. The girls who like J and L are immediate neighbours and one of them faces N, who likes F. Here we get 3 following cases: Case 1:- The girls who like K and H stand in the same circle but they are not immediate neighbours of each other. While P does not like I. so this case is not possible. Case 2:- The girl who likes K faces the girl who likes E. T who likes H faces the immediate neighbour of the girl who likes G. So this case is also not possible. Case 3:- The girl who likes K faces the girl who likes E. T who likes H faces the immediate neighbour of the girl who likes G. R who does not like G does not face T. This is the final arrangement.
2850 ÷ 2.5 - ? × 42 = 300
135÷ 15 x 19 + 14807 = ? + √3249 - √9604
25% of {(5/18) × 2880 + 122 } = ?% of 590
Find the value of 'p' in the given expression: 15 of 6 ÷ p x 4 = 30.
1540 ÷ 7 - 184 ÷ 8 = ?
65% of 102 + 14 = ? – 20
(21% of 360) ÷ 0.8 =?
Find the unknown value of' x' in the proportion $$(5x + 1) : 3 = (x + 3) : 7
350% of (450 / 1.5) = ?% of 4200
8888.88 + 888.88 + 88.88 + 8.88 = ? – 0.48