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Start learning 50% faster. Sign in nowThere are three persons sit between O and N. The person who sits two places away from N sits fourth to the right of M. M sits neither adjacent to O nor adjacent to S. The person who sits immediate left of the vacant seat sits two places away from O. 
Q does not sit adjacent to O. R sits two places away from Q. The number of persons who sits between N and R is one less than the number of persons who sits between S and Q. M does not sit at the end. Q does not sits right of N. 
T sits adjacent to N. This eliminates case 1a. The number of persons who sits between Q and P is same as the number of persons who sits between T and O. This eliminates case 1 and 1a. so final case-2 Case-2 
Statements: I < W = T ≤ H = C ≤ Y, Y > M ≥ V
Conclusions:
I. Y ≥ W
II. H > V
III. M < T
What should come in the place of question mark, in the given expressions to make ‘M < J’ always true?
M = N ≤ O = P ? K= J
Statements:
P ≤ Q < R > K; R < S > T; T < U < V
Conclusions:
I). P < S
II). P ≥ S
...Statements: I > O = D; K < J ≤ O; L > K ≥ S
Conclusions:
I. I > S
II. D ≥ L
III. S > O
Statements: E < F < N; O < Q ≤ D; F < D; R < P ≥ O
Conclusions:
I. R < D
II. D > E
III. N > Q
Statements: M % F & P % F; F # A & W; W @ O # S
Conclusions:
I. A @ O
II. M % O
III. S @ F
...Statements:
B < C < J ≤ H; W > F = T > J; P ≤ A < W
Conclusions:
I. C < A
II. P > B
Statements: M $ K; K & N, N % R, R @ W
Conclusions:
I. W & K
II. K & W ...
Statements:
Some Cloud is Thunder.
Only a few Thunder is Lighting.
No Lighting is Star.
Conclusion:
I. All Cloud can ...
Statements: H > S ≥ F = B ≤ U≤ T; E ≤ K ≤ B
Conclusions:I. U ≥ E II. S > T
