What is the difference of ages of U and S?
The age of the second eldest person is 70 year which means the age of the grandmother is 70 year. V is the brother – in- law of O. V’s age is 2 year less than O’s age and O’s age is 6 year less than S’s age. R is the mother of S and her age is 2.5 of the age of her son. From these it is clear that O, V and S belongs to second generation and R is the grandmother whose age is 70 year. Further, only the father of T is sitting between Q and V. T does not belong to third generation. So, T belongs to second generation. The person who is sitting on the immediate left of O and immediate right of R is 18 year old while Q is 10 year old. S, who is sitting next to Q, is not sitting opposite to O. Q is the female member of the family. Q is 10 year old. So, Q is the granddaughter and 10 year old. R is 4 year younger than P. Means P is 74 year old. Rest U’s age is multiple of 4 but not a perfect square. As only remaining position is that U is the grandson and is 12 year old. The person who sits immediate right of V is a male but he is not U. So, from this case 3 will be eliminated. As we know that U can’t sit between R and O, so clearly T sit between R and O and U can’t sit to immediate right of Q so from this case 2 will be eliminated. Rest we know that the age of T is 18 year so she is the daughter of P and S is the son of R and is 28 year old. Rest V is 20 year old, O is 22 year old, O is 22 year old. So, the final arrangement is –
Statements: W < B ≤ D = L, L < M ≤ K < Z
Conclusions:
I. W ≤ M
II. D < K
III. Z > B
Statements: Q > U = V ≤ X; R ≥ S ≥ X
Conclusions:
I. U = S
II. V < S
Statements: A & D, D # P, P @ Q, Q % R
Conclusions: I. D & R II. Q # A
...Statements: B < I ≥ E > K; Z ≤ N = K
Conclusions:
I. Z < E
II. N ≤ I
III. B > N
Statements: B @ E, E $ Y, Y & I, I % C
Conclusions: I. E @ I II. C & B
...In the following questions assuming the given statements to be true, find which of the conclusion among given conclusions is/are definitely true and the...
Statement: C > S > F > B > L; I > B > T
Conclusion: I. I > L II. T < C
Statements : C ≤ A < B ≤ D; E < B > F > G; I < H < G
Conclusions :
I. B > I
II. D > H
III. H < B
Statements: M # N # O $ P & Q % R % S
Conclusions : I. Q @ S ...
Statements: O ≥ M > F, K ≤ J ≤ D = F, B ≤ Z ≤ L = K
Conclusion:
I. M > L
II. D ≥ B