We have: Two person sits between A and the one whose weight is 48kg. The one whose weight is 48kg neither sits at edge nor immediate neighbor of C, that means the one whose weight is 48kg sits at corner, thus in case (1) A sits third to right of the one whose weight is 48kg, in case (2) A sits third to left of the one whose weight is 48kg. One person sits between C and A, whose weight is 123kg. C neither sits adjacent to B nor sits adjacent to E, that means in case (1) C sits second to left of A, in case (2) C sits second to right of A. The one whose weight is 123kg sits exactly opposite to the one whose weight is 53kg. Based on above given information we have: Case-1 
Again, we have: The one whose age is 126kg and C sits together, that means in case (1a) & case (2a) the one whose age is 126kg sits immediate right of C, in case (1b) & case (2b) the one whose age is 126kg sits immediate left of C. Three person sits between the one whose weight is 126kg and H. H neither sits adjacent to K nor his weight is 48kg. One person sits between E and B, whose weight is not 53kg but sits opposite to H, as E doesn’t sit adjacent to C, that means in case (1a) H sits third to left of C and weight of E is 48kg, in case (1b) H sits immediate right of A and E sits fifth to left of C, in case (1c) H sits fifth to left of C and E sits immediate right of A, in case (2a) H sits fifth to right of C and E sits immediate left of A, in case (2b) H sits third to right of C and weight of E is 48kg, in case (2c) H sits immediate left of A and E sits fifth to right of C. Based on above given information we have: 
Case-2a 
Case-2c 
Again, we have: F sits exactly between J and the one whose weight is 72kg, who sits immediate left of G. Weight of F is neither 48kg nor 64kg. Three person sits between J and the one whose weight is 36kg. H sits adjacent to the one whose weight is 36kg, that means in case (1a) weight of F is 126kg and weight of G is 36kg, in case (2c) F sits second to left of J and G sits immediate right of A and case (1b), case (1c), case (2a) and case (2b) are not valid . Based on above given information we have: 
Case (1b), case (1c), case (2a) & case (2b) are not valid as F sits exactly between J and the one whose weight is 72kg, who sits immediate left of G . Again, we have: Weight of I is thrice the weight of H, since only such possible combination are (41, 123) & (42, 126), thus weight of H must be 42kg and that of I must be 126kg. Since, weight of I is 126 Weight of L is twice the weight of H, thus weight of L is 84kg. One person sits between L and D, that means L sits immediate left of E. Difference between weight of G and E is 12kg. The one whose weight is 39kg not sits adjacent to K, that means weight of weight of G must be 51kg and weight of E is 39kg. Three person sits between the one whose weight is 51kg and the one whose weight is 64kg, thus weight of B must be 64kg. As, remaining person is F, thus weight of F must be 41kg. Case (1a) is not valid as weight of I is 126kg. Based on above given information we have final arrangement as follow: Case-2c 
The prices (in ₹) of different yarns (per kg) in two consecutive years are as follows.
Which of the following is the most relevant for deriving a point estimate?
With reference to analysis of variance. which of the following statements is/are correct?
(I) Change of origin will affect the value of F
...The memory-less property is followed by which of the following continuous distribution:
Approximately, the coefficient of variation for the given data where Pearson's second measure of skewness = 0.42, arithmetic mean- 86 and median 80, is:
If Z1, Z2,…Zn are n independent standard normal variates, then Σni=1 Z2i will follow:
The probability of getting 9 cards of the same suit in one hand at a game of bridge is
For the study purpose, the mean of the observations is 148 gm and standard deviation is 17.4 gm. Approximately, the coefficient of variation equals to:
For making frequency distribution, the number of classes used depends upon:
