C faces the one who sits third to the right of K. D sits fourth to the left of E. Neither C nor K sits adjacent to both DÂ and E. Only two persons sit between D and L who sits second to the left of H. As many persons sit between H and D is the same as between C and J. So we get Two Cases The one who sits second from J is sits second to the right of F. G sits third to the right of I. Hence the second case gets discarded so we get the final arrangement as
4 5.5 19 .5 98.5 694 6251.5
...14Â Â Â Â Â 15Â Â Â Â Â Â Â 32Â Â Â Â Â Â 99Â Â Â Â Â Â 400Â Â Â Â Â Â ?
...61 71 86 ? 131 161
...2, 12, 90, 240, ?, 1260
5, 8, 17, ?, 37, 48
Below given are 2 wrong number series.
Series I: 19, 30, 6, 45, – 11, 67
Series II: 141, 148, 223, 398, 723, 1248
I. The absolute...
[(288)2 ÷ 96 × ?] ÷ 44 = 432
6 6 13 39 ? 226
...62 90 122 158 198 ?
6Â Â Â Â Â Â Â Â Â Â Â Â Â 16Â Â Â Â Â Â Â Â Â Â 116Â Â Â Â Â Â Â Â 566Â Â Â Â Â Â Â Â 2272Â Â Â Â Â Â 6814
13       a  Â...