STEP I: M sits third to the left of I who sits an immediate neighbour of K. Three persons sit between A and K who sits second to the left of C. As per these statements, we can say that there are three possible cases and the arrangement will look like this: STEP II: E sits to the immediate left of G who sits second to the left of M. Both E and A sit adjacent to each other. The number of persons sits between G and K is one less than the number of persons sits between K and E when counted from the right of both G and K respectively. At least one person sits between C and E when counted from the right of C. As per these statements, CASE I and CASE III get eliminated and we continue with CASE II and the final arrangement will look like this:
I. x²= 961
II. y= √961
I: x² - 10x + 21 = 0
II: 4y² - 16y + 15 = 0
I. 96y² - 76y – 77 = 0
II. 6x² - 19x + 15 = 0
A and B are the roots of equation x2 - 13x + k = 0. If A - B = 5, what is the value of k?
I. 10x2 + 33x + 9 = 0
II. 2y2 + 13y + 21 = 0
Equation 1: x² - 250x + 15625 = 0
Equation 2: y² - 240y + 14400 = 0
I. 7x² + 27x + 18 = 0
II. 19y² - 27y + 8 = 0
I. 14p2 – 135p + 81 = 0
II. 7q2 – 65q + 18 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 34x + 288 = 0
Equation 2: y² - 29y + 210 = 0
I. 8a2 – 22a+ 15 = 0
II. 12b2 - 47b + 40=0