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We have, U sits opposite to the one who sits second to the left of O. Only two persons sit between K and O. K sits to the left of O. From the above condition, there are three possibilities.
Again we have, The number of persons sit to the left of U is the same as the number of persons sits to the right of Y. W sits second to the right of Y. J sits immediate left of M, none of them sits at end of the row.
Again we have, L sits opposite to the one who sits second to the left of Z. X and Y are not immediate neighbours. From the above condition, case2 and case3 get eliminated. Case1 shows the final arrangement.
Statements: A @ D % M % N; M $ P $ Q
Conclusions : I. D % Q I...
Statement:
J < K ≤ M > O; M > P < Z; Z = R
Conclusion:
I. P < K
II. R > K
Statement: N < M; G ≤ V = M; J > V; K ≥ M
Conclusion:
I. J > K
II. K ≥ J
Statements: D ≤ R < E = F, W = B > A ≥ F
Conclusions:
I. E = W
II. D < B
Statements: R > N > Z < O = I ≥ T < W < S ≤ L
Conclusion
I: L > Z
II: O > T
Statements: I < G = Z = X ≤ A ≤ R < N > D = V
Conclusions:
I. I > D
II. R ≥ G
III. X < V
Statement:M<N≥O =A ≥P;P<R;N<T
Conclusions:
I. M < R
II. T > R
Statements: E ≤ F = G ≤ H = I, M < L ≤ G = K ≥ J
Conclusion:
I. I ≤ L
II. I > M
III. E ≥ J
Statements: E $ N, N * G, H % E
Conclusions: a) G # H b) H $ N
Statement: T > U = V < W > X; Y ≤ H < S; X > Z > S
Conclusions:
I. W > Y
II. Y < Z
III. U < Z