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Only one person sits between E and the one who likes Red. A sits second to the left of the one who likes Red. If the one who likes Red sits at place no.1, then A sits at place no. 7 and E sits at place no. 3. E sits second to the left of the one who likes Black. So, the one who likes Black at place no. 5. Only two persons sit between G and the one who has likes Black. From this statement, we will have two cases: G will sit either at place no. 2 or 8. H is an immediate neighbour of C. C is not an immediate neighbour of A or E and he does not like Black. The one who likes Green sits second to the right of H. C cannot sit at places no. 6, 5, 4, and 8. So, the only place left for him is place no. 1. As H is an immediate neighbour of C. So, H will sit either at place no. 8 or 2. The one who likes Green sits either at place no. 4 or 2. Only three people sit between the one who likes Green and the one who likes Yellow. So, the one who likes Yellow sits either at place no. 6 or 8. F sits second to the left of the one who likes Yellow. So, F sits either at place no. 4 or 6.
H does not likes Blue. The one who likes Blue is not an immediate neighbor of H. D sits on the immediate left of the one who likes Blue. The one who likes Pink sits on the immediate right of the one who likes Cream. Case 1 will get discarded as the one who likes Blue cannot sit at place no. 7 and 8. If the one who likes Blue sits either at place no. 4 or 3, then there is no place for D as D sits on the immediate left of the one who likes Blue In case 2, if the one who likes Blue sits at place no. 6, then D sits at place no. 5. The one who likes Pink and the one who likes Cream sit at place no. 3 and 2 respectively Only person left for place no. 4 is B. Only colour left for A is White.
Case - 2 is the final arrangement.
Statements: A @ D % M % N; M $ P $ Q
Conclusions : I. D % Q I...
Statement:
J < K ≤ M > O; M > P < Z; Z = R
Conclusion:
I. P < K
II. R > K
Statement: N < M; G ≤ V = M; J > V; K ≥ M
Conclusion:
I. J > K
II. K ≥ J
Statements: D ≤ R < E = F, W = B > A ≥ F
Conclusions:
I. E = W
II. D < B
Statements: R > N > Z < O = I ≥ T < W < S ≤ L
Conclusion
I: L > Z
II: O > T
Statements: I < G = Z = X ≤ A ≤ R < N > D = V
Conclusions:
I. I > D
II. R ≥ G
III. X < V
Statement:M<N≥O =A ≥P;P<R;N<T
Conclusions:
I. M < R
II. T > R
Statements: E ≤ F = G ≤ H = I, M < L ≤ G = K ≥ J
Conclusion:
I. I ≤ L
II. I > M
III. E ≥ J
Statements: E $ N, N * G, H % E
Conclusions: a) G # H b) H $ N
Statement: T > U = V < W > X; Y ≤ H < S; X > Z > S
Conclusions:
I. W > Y
II. Y < Z
III. U < Z