Statements:
All nice are tampered.
All tampered are beaten.
All mixed are beaten.
Conclusions:
I. No tampered is mixed.
II. Some mixed are tampered.
III. Some beaten are nice.
IV. Some mixed are nice
All mixed are beaten(A) + All tampered are beaten ⇒ Conversion ⇒ Some beaten are tampered (I) ⇒ No conclusion. Hence neither conclusion I nor II follow but they will form a complementary pair. Hence either conclusion I or II follows. All nice are tampered(A) + All tampered are beaten ⇒ All nice are beaten (A) ⇒ Conversion ⇒ Some beaten are nice (I). Hence conclusion III follow. All nice are tampered(A) + All tampered are beaten ⇒ All nice are beaten (A) + All tampered are beaten ⇒ Conversion ⇒ Some beaten are tampered (I) ⇒ No conclusion. Hence conclusion IV does not follow. ALTERNATE SOLUTION:
78.89 × 81.03 – (16.83)² + 8.33% of 9602.87 = ? – 50.23
1220 ÷ 61 ÷ 5 + 450 of 20% - 70 = √ ?
4261 + 8234 + 2913 + 8217 + 6283 + 4172 =?
25% of 400 + 3 × 102 = ?2
104 × 21 ÷ 13 + ? % of 300 = 320 + 22
1549.8 ÷ 8.2 + 65.6 × 55 = (? × 4) + (42 × 30.5)
√( (664+ √(136+ √(59+ √(21+ √(7+ √81) ) ) ) ) ) = ?
[4(1/3) + 4(1/4)] × 24 – 62 = ?2
(5/7) of (7/11) of (3/5) of 52% of 4400 = ? - (44)2 + (50)2 - (62% of 1750) - (188 ÷ 9.4)
756 + 432 – 361 + ? = 990