Statements:
All pineapple are peach.
All peach are cherry.
All cherry are papaya.
Conclusions:
I. All cherry are pineapple.
II. All papaya may be pineapple.
All pineapple are peach (A) + All peach are cherry(A) = All pineapple are cherry(A) ⇒ Conversion ⇒ Some cherry are pineapple(I). Hence, conclusion I will not follow. All pineapple are peach(A) + All peach are cherry(A) = All pineapple are cherry(A) + All cherry are papaya(A) = All pineapple are papaya (A) ⇒ Conversion ⇒ Some papaya are pineapple(I) ⇒ Probable conclusion ⇒ All papaya may be pineapple(A). Hence, conclusion II will follow.
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