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No mouse is a keyboard(E) + Some keyboards are printers(I) ⇒ Some printers are not mouse(O*). Hence, conclusion I follows. Some keyboards are printers(I) + All printers are scanners(A) ⇒ Some keyboards are scanners(I) ⇒ Probable conclusion ⇒ All scanners may be keyboards. Hence, conclusion II follows.
I. x2 = 10
II. y2 - 9y + 20 = 0
...I. 2x² - 12x + 16 = 0
II. 4y² - 8y - 12 = 0
I. 40x² + 81x + 35 = 0
II. 63y² + 103y + 42 = 0
I. 5q = 7p + 21
II. 11q + 4p + 109 = 0
I. 6x2- 47x + 77 =0
II. 6y2- 35y + 49 = 0
I. 8y2- 2y - 21 = 0
II. 2x2+ x - 6 = 0
The quadratic equation (p + 1)x 2 - 8(p + 1)x + 8(p + 16) = 0 (where p ≠ -1) has equal roots. find the value of p.
I. 8x² + 2x – 3 = 0
II. 6y² + 11y + 4 = 0
I. x2 + x – 42 = 0
II. y2 + 6y – 27 = 0
I. 8a2 – 22a+ 15 = 0
II. 12b2 - 47b + 40=0