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From Statement I. Some Lids are Spoons (I) + Some Spoons are Utensils (I) → Probable conclusion → No Lids may be Utensils (I). Hence conclusion I follows. Some Spoons are Utensils (I) + Some Utensils are plates (I) → No conclusion. Hence neither conclusion II nor III follow. From Statement II. No Lids is Spoons (E) + Some Spoons are Utensils (I) → Some Utensils are not Lids (O*) → Probable conclusion → All Lids may be Utensils (I). Hence conclusion I does not follow. Some Spoons are Utensils (I) + Some Utensils are plates (I) → No conclusion. Hence neither conclusion II nor III follow. From Statement III. Each Lids are Spoons (A) + Some Spoons are Utensils (I) → Probable conclusion → No Lids may be Utensils (I). Hence conclusion I follows. Some Spoons are Utensils (I) + No Utensil is Plate (E) → Some Spoons are not plates (O). Hence conclusion II follows. All Cups are Lids (A) + Each Lids are Spoons (A) → All Cups are Spoons (A) → Conversion → Some Spoons are Cups (I). Hence conclusion III follows. From Statement IV. No Lid is a Spoon (E) + No Spoon is a Utensil (E) → Probable conclusion → No Lid may be Utensil (I). Hence conclusion I follows. No Spoon is a Utensil (E) + No Utensil is a Plate (E) → No conclusion. Hence conclusion II does not follow. All Cups are Lids (A) + No Lid is a Spoon (E) → No Cup is a Spoon (E). Hence conclusion III does not follow.
Statements:
P ≥ Q = R; S = T ≤ U ≥ P
Conclusion:
I. R < S
II. T ≤ Q
Which among the following signs correctly fit in the blank in the same order B _ C _ D _ E _ F _ G _ H, in order to make the expressions D ≤ F and H >...
Statement: C < X ≤ B > E < L < I
Conclusion: I. X > L II. B > C
Which of the following symbols should replace the question mark (?) in the given expression in order to make the expressions B ≤ D as well as F > B de...
Statements:
E = F > Q = A > B; J < Z ≤ A
Conclusions:
I. Q > Z
II. B ˃ J
Statements: G < O = H ≥ L > F < U≤ T ≥ Z
Conclusion:
I. L ≤ O
II. T > L
Statements: D ≥ E < F = G; M < E = N ≥ O
Conclusions: I. G > M II. N < G
Statements: A < B ≤ C > E; F = I ≤ B > G; J > K = G < D
Conclusions:
I. C ≥ F
II. E < I
III. D > C
Statements: P ≥ Q > S< T > R = U
Conclusions: I. P < S
II. U = S
Statements:
P > Q < R; T ≤ U ≤ Q > S; V ≤ W < T
Conclusions:
I). P > V
II). T = S
III). R > V...