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From Statement I. Some Menus are Scanners (I) + All Scanners are Manuals (A) → Some Menus are Manuals (I) → Probable conclusion → All Manuals can be Menus (A). Hence conclusion I follows. No Printer is a Menu (E) + Some Menus are Scanners (I) → Some Scanners are not Printers (O*). Hence conclusion II does not follow. From Statement II. All Menus are Manuals (A) → Probable conclusion → All Manuals can be Menus (A). Hence conclusion I follows. All Scanners are Printers(A) → Conversion → Some Printers are Scanners (I). Hence conclusion II follows. From Statement III. Only a few Manuals are Scanners (I) + Only a few scanners are Menus (I) → Probable conclusion → All Manuals can be Menus (A). Hence conclusion I follows. Only a few scanners are Menus (I) + A few Menus are Printers (I) → No conclusion. Hence conclusion II does not follow. From Statement IV. Only a few Manuals are Printers + [All Menus are Printers (A) → Conversion] → Some Printers are Menus (I) → Probable conclusion → All Manuals can be Menus (A). Hence conclusion I follows. Only a few Manuals are Printers (I) + [All Manuals are Scanners (A) → Conversion] → Some Scanners are Manuals (I) → No conclusion. Hence conclusion II does not follow.
Statements: D = E ≥ G = K, O > B ≤ C = K, E ≤ I < F
Conclusions: I.F > K II. I ≥ G
...In the question, assuming the given statements to be true, find which of the following conclusion(s) among the three conclusions is/are true and then g...
Statements: P % Q, P $ R, Q # S, R @ T
Conclusions:
I. R $ Q
II. S & T ...
Which of the following will be definitely true if the given expression Y > Z ≥ H > J ≥ P > Q = R ≤ K > E ≤ F is definitely not true?
Statements: S > T > W = U ≤ V ≤ I, X > Y = S
Conclusions:
I. W > Y
II. I ≥ T
III. U < Y
Statements: R © K, K * N, N $ J, J % H
Conclusions: I.R $ N II.J @ K �...
Statements: A @ D % M % N; M $ P $ Q
Conclusions : I. D % Q I...
Which of the following symbols should replace the sign (@) and (%) respectively in the given expression in order to make the expression C ≥ G and A >...
Statements: P < Q = S ≥ U; V ≤ P ≥ N > I
Conclusions: I. U < V II. Q > I
...Statements: U ≥ V = W; V > X ≥ Y; X ≥ Z < T
Conclusions
I. T > Y
II. Z < U