Some mobiles may not be papers. Some dusters are not calculators
Some mobiles are calculators(I) + All calculators are papers(A) ⇒ Some mobiles are papers(I) ⇒ Probable conclusion ⇒ Some mobiles may not be papers(O). All calculators are papers (A) + No paper is a duster(E) ⇒ No calculator is a duster (E) ⇒ conversion ⇒ Some dusters are not calculators(O). By elimination method - By option 1, No + no = no definite conclusion can be drawn between duster and calculator. Hence it is eliminated. By option 2, No + some = Some calculators are not duster. But we can’t conclude that some dusters are not calculators. Hence it is eliminated. By option 3, few + no = Some mobiles are not papers. So possibility can’t be drawn. Hence it is eliminated. By option 4, the conclusion can be drawn. Hence answer is 4.
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