In the following questions, the symbols @, #, %, $ and * are used with the following meaning as illustrated below.
‘A @ B’ means ‘A is not smaller than B’
‘A # B’ means ‘A is neither smaller than nor equal to B’
‘A % B’ means ‘A is neither smaller than nor greater than B’
‘A $ B’ means ‘A is not greater than B’
‘A * B’ means ‘A is neither greater than nor equal to B’
Statements: F% G, H * I, D # F, G @ H
Conclusion:I. D # H II. G @ D III. I $ G
Decoded statement: F = G, H < I, D > F, G ≥ H Decoded conclusion: I. D > H II.G ≥ D III. I ≤ G Combined Inequalities: I > H ≤ F = G < D I > H ≤ F = G < D H < D. Hence conclusion I is true. I > H ≤ F = G < D G < D. Hence conclusion II is not true. I > H ≤ F = G < D No relationship can be established between I and G. Hence conclusion III is not true.
Statements: P % Q, Q $ B, B * C, N $ C
Conclusion:I. P % B II. B # P III. Q @ N
Decoded statement: P = Q, Q ≤ B, B < C, C ≥ N Decoded conclusion: I. P = B II.B > P III. Q ≥ N Combined Inequalities: P = Q ≤ B < C ≥ N P = Q ≤ B < C ≥ N Q ≤ B. Hence either conclusion I or II is true. P = Q ≤ B < C ≥ N No relationship can be established between Q and N. Hence conclusion III is not true
Statements: G @ H, E # F, F % G, D # E
Conclusion:I. F # H II. F % H III.D # H
Decoded statement: G ≥ H, E > F, F = G, D > E Decoded conclusion: I. F > H II.F = H III. D > H Combined Inequalities: D > E > F = G ≥ H D > E > F = G ≥ H F ≥ H. Hence either conclusion I or II is true. D > E > F = G ≥ H D > H. Hence conclusion III is true.
Statements: A @ B, Y $ Z, X * Y, Z * A
Conclusion: I. X $ A II. A % Y III. Z # Y
Decoded statement: A ≥ B, Y ≤ A, X < Y, Z < A Decoded conclusion: I. X ≤ A II.A = Y III. Z > Y Combined Inequalities: X < Y ≤ A ≥ B OR Z < A ≥ Y > X X < Y ≤ A ≥ B X < A. Hence conclusion I is not true. X < Y ≤ A ≥ B Y ≤ A. Hence conclusion II is not true. Z < A ≥ Y > X No relationship can be established between Z and Y. Hence conclusion III is not true.
Statements: P % Q, Q $ R, R @ S, O * P
Conclusion: I. P @ S II. R # O III. S # P
Decoded statement: P = Q, Q ≤ R, R ≥ S, O < P Decoded conclusion: I. P ≥ S II.R > O III. S > P Combined Inequalities: O < P = Q ≤ R ≥ S O < P = Q ≤ R ≥ S No relationship can be established between P and S. Hence either conclusion I or III is true. O < P = Q ≤ R ≥ S R > O. Hence conclusion II is true.